1+x^2=2.56x^2

Solution for 1+x^2=2.56x^2 equation:

1+x^2=2.56x^2

We move all terms to the left:

1+x^2-(2.56x^2)=0

We get rid of parentheses

x^2-2.56x^2+1=0

We add all the numbers together, and all the variables

-1.56x^2+1=0

a = -1.56; b = 0; c = +1;
Δ = b2-4ac
Δ = 02-4·(-1.56)·1
Δ = 6.24
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{6.24}}{2*-1.56}=\frac{0-\sqrt{6.24}}{-3.12}
=-\frac{\sqrt{}}{-3.12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{6.24}}{2*-1.56}=\frac{0+\sqrt{6.24}}{-3.12}
=\frac{\sqrt{}}{-3.12}
$